The distance from Seymour, Indiana to Providence, Rhode Island

The exact distance between Seymour, Indiana and Providence, Rhode Island is 786 miles (1265 kilometers) by a straight line.

The distance from Seymour, Indiana to Providence, Rhode Island
The distance from Seymour, Indiana to Providence, Rhode Island by highways is about 951 miles and it is subject to a slight change depending on the chosen route. Travel time from Seymour, Indiana to Providence, Rhode Island by car is about 15.9 hours and it also may vary depending on traffic. If you travel from Seymour to Providence please keep in mind that travel times may become much longer in case of traffic jams or bad weather. You can also use a public transport system to move between Seymour, Indiana and Providence, Rhode Island.



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Where next? Distances to other cities from Providence, Rhode Island: