The distance from Seymour, Connecticut to Providence, Rhode Island

The exact distance between Seymour, Connecticut and Providence, Rhode Island is 91 miles (146 kilometers) by a straight line.

The distance from Seymour, Connecticut to Providence, Rhode Island
The distance from Seymour, Connecticut to Providence, Rhode Island by highways is about 98 miles and it is subject to a slight change depending on the chosen route. Travel time from Seymour, Connecticut to Providence, Rhode Island by car is about 1.6 hours and it also may vary depending on traffic. If you travel from Seymour to Providence please do not forget that travel times may differ from the above in case of traffic jams or bad weather. You can also use a public transport system to move between Seymour, Connecticut and Providence, Rhode Island.



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Where next? Distances to other cities from Providence, Rhode Island: